full url to the intermediary picture

[veez]

hello,

How do I obtain the full url to the intermediary picture.

I need this information to display this on the intermediary page.  And the file that I am trying to get this information into is the theme.php.

So is there a variable I can call in the intermediary section of the theme.php page?

so that it shows the full address as http://www.mysite.com/albums/userpics/1001/pic1.jpg.

Thanks

[veez]

I intend to put some javascript in theme.php


//********************************************
// HTML template for intermediate image display
//*********************************************

How can I extract the absolute path to the intermediary picture displayed.

[Timos-Welt]

1. Check if your theme.php has function theme_html_picinfo.
2. If not, copy it from sample theme's theme.php to your theme.php.
3. Find this line:

Code Select Expand

return $html;
4. Before it, paste the following, replacing path.to.your.gallery.com with the URL to your gallery:

Code Select Expand


global $CURRENT_PIC_DATA;
$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$html .= sprintf($template, 'Intermediate size URL', '<a href="http://path.to.your.gallery.com/'.$picture_url.'">http://path.to.your.gallery.com/'.$picture_url.'</a>');

5. Enjoy.

[veez]

thanks for the reply.

here's what I have done:

I put the code you stated inside theme.php.  Just above the following


I am trying to call the function inside html template for intermediary picture as follows.
<script language="javascript">
                  var fulladdress=theme_html_picinfo(&info);

                  document.write(fulladdress);
                  </script>

Full code below:

Code Select Expand



function theme_html_picinfo(&$info)
{
    global $lang_picinfo;

    $html = '';

    $html .= "        <tr><td colspan=\"2\" class=\"tableh2_compact\"><b>{$lang_picinfo['title']}</b></td></tr>\n";
    $template = "        <tr><td class=\"tableb_compact\" valign=\"top\" >%s:</td><td class=\"tableb_compact\">%s</td></tr>\n";
    foreach ($info as $key => $value) $html .= sprintf($template, $key, $value);

global $CURRENT_PIC_DATA;
$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$html .= sprintf($template, 'Intermediate size URL', '<a href="http://mysite.com/'.$picture_url.'">http://mysite.com/'.$picture_url.'</a>');



    return $html;
}


//********************************************
// HTML template for intermediate image display
//*********************************************
$template_display_media = <<<EOT


       <!--new stuff-->


<script language="javascript">
var fulladdress=theme_html_picinfo(&info);

document.write(fulladdress);
</script>
<!--END OF NEW STUFF-->




[veez]

I am not sure if called the function properly when declaring the variable in the javascript

[veez]

Just to clarify.

What I am after is the full path to the intermediary picture so that I can use it in a javascript variable as follows:

Code Select Expand


//********************************************
// HTML template for intermediate image display
//*********************************************
$template_display_media = <<<EOT


       <!--new stuff-->


<script language="javascript">
[b]var fulladdress[/b]=theme_html_picinfo(&info);

document.write(fulladdress);
</script>
<!--END OF NEW STUFF-->


[SaWey]

You can't call a php function from javascript, what you should do is create the javascript variable dynamically like so:

Code (php) Select Expand


$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$javascript_pic_url = 'http://mysite.com/' . $picture_url;

$template_display_media = <<<EOT
       <!--new stuff-->
<script language="javascript">
var fulladdress = "$javascript_pic_url";
document.write(fulladdress);
</script>
      <!--END OF NEW STUFF-->
EOT;




[veez]

firstly thank for looking into this, SaWey

I copied the exact code you stated into theme.php.
I noticed that $picture_url is outputting nothing.
So it outputs only :http://mysite.com/

So I tried adding the following line before your code like Timos-Welt had in his code:
But that did not make  a difference:  global $CURRENT_PIC_DATA;

Note I did not use any of Timos-welt's code here

Code Select Expand


global $CURRENT_PIC_DATA;
$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$javascript_pic_url = 'http://mysite.com/' . $picture_url;

//********************************************
// HTML template for intermediate image display
//*********************************************
$template_display_media = <<<EOT


<!--new stuff-->
<script language="javascript">
var fulladdress = "$picture_url";
document.write(fulladdress);

//document.write("hello");
</script>
      <!--END OF NEW STUFF-->



[SaWey]

This is what I tried, as I suggested:

Code Select Expand


function theme_html_picinfo(&$info)
{
    global $lang_picinfo, $CURRENT_PIC_DATA;

$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$javascript_pic_url = 'http://mysite.com/' . $picture_url;

$html .= <<<EOT
       <!--new stuff-->
<script language="javascript">
var fulladdress = "$javascript_pic_url";
document.write(fulladdress);
</script>
      <!--END OF NEW STUFF-->
EOT;


    $html .= "        <tr><td colspan=\"2\" class=\"tableh2_compact\"><b>{$lang_picinfo['title']}</b></td></tr>\n";
    $template = "        <tr><td class=\"tableb_compact\" valign=\"top\" >%s:</td><td class=\"tableb_compact\">%s</td></tr>\n";
    foreach ($info as $key => $value) $html .= sprintf($template, $key, $value);

    return $html;
}


Works without a problem.

[veez]

Having some problems:

First let me give an outline of the intermediate page layout;

[picture]
[picture title]
[picture description]
[filmstrip]
[rating]
[file information]
[add your comment]

with that setup,  the full url is displayed in the "file information section"

I would like to display the full address right below the [picture title]  by adding the code into $template_display_media in theme.php


I tried entering the quoted code into $template_display_media but could not display it.

I am confused as the variable $template_display_media is a php variable that is holding html information.
Now I need to use php inside this variable.

So this is what i tried

I have cut out the needed code from the previous example

Code Select Expand


global $lang_picinfo, $CURRENT_PIC_DATA;

$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$javascript_pic_url = 'http://mysite.com/' . $picture_url;


     
<script language="javascript">
var fulladdress = "$javascript_pic_url";
document.write(fulladdress);
</script>
   


and tried pasting into $template_display_media in theme.php but without success as follows:

Code Select Expand


// HTML template for intermediate image display
$template_display_media = <<<EOT



<?php
global $lang_picinfo, $CURRENT_PIC_DATA;

$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$javascript_pic_url = 'http://mysite.com/' . $picture_url;


     
<script language="javascript">
var fulladdress = "$javascript_pic_url";
document.write(fulladdress);
</script>
?>






        <tr>
                <td align="center" class="display_media" nowrap="nowrap">
                        <table cellspacing="2" cellpadding="0" class="imageborder">
                                <tr>
                                        <td align="center">
                                                {IMAGE}

                                        </td>
                                </tr>
                        </table>
                </td></tr>
                <tr><td>
                                                <table width="100%" cellspacing="2" cellpadding="0" class="tableb">
                                <tr>
                                        <td align="center">

                                                {ADMIN_MENU}
                                        </td>
                                </tr>
                        </table>





<!-- BEGIN img_desc -->
                        <table cellpadding="0" cellspacing="0" class="tableb" width="100%">
<!-- BEGIN title -->
                                <tr>
                                        <td class="tableb"><center><b>
                                                {TITLE}
                                        </b></center></td>
                                </tr>
<!-- END title -->
<!-- BEGIN caption -->
                                <tr>
                                        <td class="tableb"><center>
                                                {CAPTION}
                                        </center></td>
                                </tr>
<!-- END caption -->
                        </table>
<!-- END img_desc -->
                </td>
        </tr>

EOT;



Thanks for the previous replies.  Hopefully this can be resolved.  I messed around with it for a while w/o success.
Another confusion is that the variable $template_display_media is a php variable and then I am putting more php into it by using

<?php

code
?>

[veez]

Okay, perhaps that was too specific.

Could someone please tell me how to get the full url to the image when putting it in a new function.


From the previous code snippets,  I tried to make a new function and use the full address to the intermediary picture

Code Select Expand


function newfunction()
{

global $lang_picinfo, $CURRENT_PIC_DATA;


$picture_url = get_pic_url($CURRENT_PIC_DATA, 'normal');
$name = 'http://mysite.com/' . $picture_url;

return $name;
}



When I try to output it, the variable, $picture_url is empty.

Any ideas?

Thanks