Album Name format in 'File information' Album Name format in 'File information'
 

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Album Name format in 'File information'

Started by cocoon, September 07, 2004, 02:19:03 PM

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cocoon

When I (as the admin), create a new album anywhere on the site, the file info for photos in that album shows:

Album Name: Admin / Album Name

Is there any way I can change it to:

Album Name: Album Name

Or have I just created the albums incorrectly?  :P

Joachim Müller

you (as an admin) shouldn't create albums within user galleries, as the whole Coppermine gallery is your "user gallery" in a broader sense. Create albums in "regular" categories (you will have to create them first using the "Categories" link in your admin menu. I recommend taking a look into the coppermine documentation, as this is explained there as well.

Joachim

cocoon

I am not creating albums within user galleries.
The user galleries section is empty.

The albums I have created using the 'Categories' link on the admin menu are displaying as in my first post.

Any ideas?

Casper

Open displayimage.php, and find this code;

$info[$lang_picinfo['Album name']] = '<span class="alblink">' . $owner_link . $ipinfo . '<a href="thumbnails.php?album=' . $CURRENT_PIC_DATA['aid'] . '">' . $CURRENT_ALBUM_DATA['title'] . '</a></span>';

Now change it to this;

$info[$lang_picinfo['Album name']] = '<span class="alblink">'  '<a href="thumbnails.php?album=' . $CURRENT_PIC_DATA['aid'] . '">' . $CURRENT_ALBUM_DATA['title'] . '</a></span>';

Not tested, so back up first.
It has been a long time now since I did my little bit here, and have done no coding or any other such stuff since. I'm back to being a noob here

cocoon

Thanks Casper!

With a slight modification, worked a treat.

The replacement code:

$info[$lang_picinfo['Album name']] = '<span class="alblink">'  '<a href="thumbnails.php?album=' . $CURRENT_PIC_DATA['aid'] . '">' . $CURRENT_ALBUM_DATA['title'] . '</a></span>';

Should be:

$info[$lang_picinfo['Album name']] = '<span class="alblink"><a href="thumbnails.php?album=' . $CURRENT_PIC_DATA['aid'] . '">' . $CURRENT_ALBUM_DATA['title'] . '</a></span>';

*sigh of relief*